G(x)=(x^2-3x+16)/x

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Solution for G(x)=(x^2-3x+16)/x equation: 



(G)=(G^2-3G+16)/G

We move all terms to the left:

(G)-((G^2-3G+16)/G)=0



Domain of the equation: G)!=0

G!=0/1

G!=0

G∈R



We multiply all the terms by the denominator


G*G)-((G^2-3G+16)=0

Wy multiply elements

G^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$G=\frac{-b}{2a}=\frac{0}{2}=0$

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